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Working principle of a Current Mirror

Last updated Dec 17, 2022

A Current Mirror copies the golden reference current $I_{ref}$ generated by a Band Gap Reference circuit.

# Circuit Diagram

# Explanation

# Equations

Transistor Q1 is diode-connected which means that the collector-base voltage is zero. Q1 and Q2 share the same base-emitter voltage. Assume that the output impedance of Q2 is infinite. The voltage to turn on transistor Q1 is $V_{BE(on)}$ .

If the transistors Q1 and Q2 are equal, $I_{c1} = I_{c2}$ and $I_{b1}=I_{b2}=I_{c1}/\beta_f$

Summing currents at the collector of Q1, $I_{ref} - I_{c1} -I_{b1} - I_{b2} = 0$

Substituting for $I_{b1}$ and $I_{b2}$, $I_{ref} - I_{c1}(1+2/\beta_f)=0$

or, $I_{c1} = I_{ref}/(1+2/\beta_f)$

If $\beta_f$ » 1, then $I_{c1}=I_{c2}=I_{ref}$

Hence, to refer the current back to the supply voltages, $$ I_{c2}= \frac{V_{ref} - V_{BE(on)}}{R} = I_{ref} $$


# References